'javac' is not recognized as an internal or external command, Program Files (x86)Microsoft Visual Studio 8Common7IDEPrivateAssemblies Program Files (x86)Microsoft SQL Server90ToolsBinnVSShellCommon7IDE C: (x86)Microsoft SQL Server80ToolsBinn C:Program Files (x86)Microsoft SQL SĮrver90Toolsbinn C:Program Files (x86)Microsoft SQL Server90DTSBinn C: X86)AMD APPbinx86_64 C:Program Files (x86)AMD APPbinx86 C:Windowssystemģ2 C:Windows C:WindowsSystem32Wbem C:WindowsSystem32WindowsPowerShellv1.Ġ C:Program Files (x86)ATI TechnologiesATI.ACECore-Static C:Program Files I have removed all java paths setting in path variable, removed JAVA_HOME variable, and still CMD shows 64-bit.Ĭ:oraclexeapporacleproduct10.2.0serverbin C:Python33 C:Program Files ( I have path and JAVA_HOME as system variables only, no any such user variables. I have restarted CMD after every changes to path or Java Control Panel.
Please help me on this, I want to change Java to 32-bit without un-installing 64-bit. In Java Control Panel->Java->Java Runtime Environment Settings->User, I have completed wizard to find 32-bit Java and enabled that only, with disabling 64-bit installation, but still CMD shows same output. Then added JAVA_HOME variable with value C:Program Files (x86)Javajdk1.7.0_02, but still CMD shows same output. I have specified only 32-bit installation path in path variable, but still CMD shows same output for java -version command. Removed path to 64-bit installation from path variable, but still CMD shows same output for java -version command. Java HotSpot(TM) 64-Bit Server VM (build 24.0-b56, mixed mode)
Java(TM) SE Runtime Environment (build 1.7.0_40-b43)
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